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=1.5Y^2-6Y+3
We move all terms to the left:
-(1.5Y^2-6Y+3)=0
We get rid of parentheses
-1.5Y^2+6Y-3=0
a = -1.5; b = 6; c = -3;
Δ = b2-4ac
Δ = 62-4·(-1.5)·(-3)
Δ = 18
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18}=\sqrt{9*2}=\sqrt{9}*\sqrt{2}=3\sqrt{2}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-3\sqrt{2}}{2*-1.5}=\frac{-6-3\sqrt{2}}{-3} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+3\sqrt{2}}{2*-1.5}=\frac{-6+3\sqrt{2}}{-3} $
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